Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeDévelopper le produit suivant `(3x1)(2x4)` renverra `3*x*2*x3*x*42*x4` Le développement de cette expression algébrique `(x2)^3` renverra `2^33*x*2^23*2*x^2x^3` On note que le résultat n'est pas renvoyé sous son expression la plus simple et ce afin de pouvoir suivre les étapes du calculs Pour simplifier le résultat, il suffit d'utiliser la fonction réduire Développement enZ = 1 Circle x 2 y = 1 z = 2 Circle x 2 y = 2 z = 3 Circle x2 y2 = 3 (b) Sketch all the traces that you found in part (a) on the same coordinate axes (c) Compute equations for the traces in the y = 0, y = 1, y = 2, and y = 3 planes Plane Trace y = 0 Parabola z = x2 y = 1 Parabola z = x2 1 y = 2 Parabola z = x2 4 y = 3 Parabola z = x2 9 (d) Sketch all the traces that you found in
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Which graph most closely represents (x+2)2+(y+1)2=9
Which graph most closely represents (x+2)2+(y+1)2=9-X^2 2 y^2 = 1 Natural Language;Arrow_forward Question a Graph y = e x and y = 1 x x 2 /2 in the same viewingrectangle b Graph y = e x




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Since y^2 = x − 2 is a relation (has more than 1 yvalue for each xvalue) and not a function (which has a maximum of 1 yvalue for each xvalue), we need to split it into 2 separate functions and graph them together So the first one will be y 1 = √ (x − 2) and the second one is y 2 = −√ (x − 2)$\endgroup$ – user Aug 8 '14 at 1803Graph an exponential function with transformations
Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeIt will plot functions given in the form y = f(x), such as y = x 2 or y = 3x 1, as well as relations of the form f(x,y) = g(x,y), such as x 2 y 2 = 4 To use the plot command, simply go to the basic plot page, type in your equation (in terms of x and y), enter the set of x and y values for which the plot should be made and hit the "Plot" button Your equation will be automatically plotted$\endgroup$ – diracdeltafunk Sep 16 '12 at 2252 $\begingroup$ No problem!
Graph y = ex and y = 1 x x2/2 x3/6in the sameviewing rectanglec Graph y = ex and y = 1 x x2/2 x3/6 x4/24 in thesame viewing rectangled Describe what you observe in parts (a)–(c) Try generalizing this observation close Start your trial now!I am already using it and I only can plot in 2 dimensional graph Can someone help me with this problem?First week only $499!




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About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators If we look at the two functions in the given interval we see that #y=9x^2# attains greater values than #y=x1# therefore #y=9x^2# is above #y=x1# in the given interval The area between these two functions in the given interval will be BONJOUR Voila mon problème Résoudre x^2 x 2 =0 j'ai calculé le discriminant donc x=2 et x=1 après vérification 2 OK mais 1 1^2 1 2 = 2 Y 'a




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$\begingroup$ why would yaxix and zaxis be parallel ?Use the center, vertices, and asymptotes to graph the hyperbola (x 1)^2 9(y 2)^2 = 9 (x1)^2/9 (y2)^2 = 1 This is aOr are you doing something else?




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The left curve is the sideways parabola x = y2 The right curve is the straight line y = x − 2 or x = y 2 The limits of integration come from the points of intersection we've already calculated In this case we'll be adding the areas of rectangles going from the bottom to the top (rather than left to right), so from y = −1 to y = 2Graph y^29=x Rewrite the equation as Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Cancel the common factor of and Tap for more1 x 2 2 z 2 = 1 forms an ellipse in the x z plane y can be anything you like, so in three dimensions this looks like a cylinder centered around the y axis except with an ellipse instead of a circle (the ellipse has a semi major axis of length 1 in the x direction and a semi minor axis of length 1 2 in the z direction)




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X 2 4 y 2 9 z 2 = 1 Multiply both sides of the equation by 36, the least common multiple of 4,9 Multiply both sides of the equation by 3 6, the least common multiple of 4, 9 36x^ {2}9y^ {2}4z^ {2}=36 3 6 x 2 9 y 2 4 z 2 = 3 6 Subtract 36x^ {2} from both sides Subtract 3 6 x 2 Draw a circle with (3, 1) as center and 3 as radius Standard equation of a circle with (a, b) as center and r as radius is (xa)^2(yb)^2=r^2 Hence, in the above, (3, 1) is the center and 3 is the radius Hence to draw the graph, just draw a circle with (3, 1) as center and 3 as radiusExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge




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Graph {eq}(x 2)^2 (y 1)^2 = 9 {/eq} Circles A circle is a two dimensional relationship for which every point is equally distant from the point in the centerAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, andTrigonometry Graph (x2)^2 (y1)^2=9 (x 2)2 (y 1)2 = 9 ( x 2) 2 ( y 1) 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of



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Graph x^2y^2=9 x2 y2 = 9 x 2 y 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset from theIf you don't include an equals sign, it will assume you mean "=0" It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations If you justDemonstration of how to graph an equation in slope intercept form interpreting the slope at the coefficient of x and the constant term as the yinterceptSlo



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Graph each set of functions on the same coordinate axes Describe in what way the graphs are the same and in what way they are different 1 y = x 2 y = 2 x 2 y = 4 x 2 2 y = 1 4 x 2 y = − x 2 y = − 4 x 2 3 y = 1 4 x 2 y = x 2 − 2 y = 1 4 x 2 − 2 4 y = x 2 y = − x 2 y = (x 2) 2 y = − (x 2) 2 Set The points F (0, 1), D (0, − 1Graph (x1)^2 (y2)^2=9 (x − 1)2 (y 2)2 = 9 (x 1) 2 (y 2) 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circlePlot x^2 3y^2 z^2 = 1 Natural Language;




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Solution Graph X 3 2 Y 1 2 4 Y 2 2 4 4 1 X 1 X 2 2 9 Y 3 2 4 1 X 2 2 4 Y 3 2 9 1 Thanks Soo Much
The same way you plot anything Even with this equation being complicated looking, just assume that this elliptical mapping has some yvalue(s) for whatever xvalue(s) Since this is second order, we can expect it to have some values So, start ofGraphs Solve Equations Calculus Derivatives Integrals Limits Algebra Calculator Trigonometry Calculator Calculus Calculator Matrix Calculator Solve algebra trigonometry statistics calculus matrices variables list Solve for x, y x=3\text{, }y=1x=2\text{, }y=1 x = 3, y = 1 x = 2, y = − 1 Graph Quiz Algebra 5 problems similar to x ^ { 2 } x y y ^ { 2 } = 7,2 x yContourPlot3Dx^2 y^2 == 1, {x, 2, 2}, {y, 2, 2}, {z, 2, 2} Share Improve this answer Follow answered Sep 16 '12 at 2247 Mark McClure Mark McClure 315k 3 3 gold badges 97 97 silver badges 156 156 bronze badges $\endgroup$ 2 $\begingroup$ Oh, great!
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In this math video lesson I show how to graph y=(1/2)x2 The equation in this video is in slopeintercept form, y=mxb, and is a common way to graph an equ$\begingroup$ How did you get negative 1/2 if one divides both sides by 2 to get rid of the 2 that is adjacent to the quantity (y1)^2?Have fun Ben $\endgroup$ –




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Subtracting x 2 from itself leaves 0 \left (y\sqrt 3 {x}\right)^ {2}=1x^ {2} ( y 3 x ) 2 = 1 − x 2 Take the square root of both sides of the equation Take the square root of both sides of the equation y\sqrt 3 {x}=\sqrt {1x^ {2}} y\sqrt 3 {x}=\sqrt {1x^ {2}} y 3 x = 1 − x 2 y 3 x = − 1 − x 2Graph the ellipse and its foci x^2/9 y^2/4=1 standard forms of ellipse (xh)^2/a^2(yk)^2/b^2=1 (horizontal major axis),a>b (yk)^2/a^2(xh)^2/b^2=1 (vertical major axis),a>b given ellipse has horizontal major axis center(0,0) a^2=9 a=3 b^2=4 b=2 c=sqrt(a^2b^2)=sqrt(94)=sqrt(5)=224 foci=(224,0),(224,0) see graph of given ellipse below y=((364x^2)^5)/3Plotting graphics3d Share Improve this question Follow asked Nov 29 '15 at 533 user user 11 1 1 gold badge 1 1 silver badge 2 2 bronze badges $\endgroup$ 2 2 $\begingroup$ (1) What do you mean by "I




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Graph a y = 3 b x=2 Solution a We may write y = 3 as Ox y =3 Some solutions are (1, 3), (2,3), and (5, 3) b We may write x = 2 as x Oy = 2 Some solutions are (2, 4), (2, 1), and (2, 2) 74 INTERCEPT METHOD OF GRAPHING In Section 73, we assigned values to x in equations in two variables to find the corresponding values of y The solutions of an equation in two variables thatYou can put this solution on YOUR website!The graph of mathx^2(y\sqrt3{x^2})^2=1/math is very interesting and is show below using desmos



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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeX^2y^2=9 (an equation of a circle with a radius of 3) sin(x)cos(y)=05; How to plot 3 dimensional graph for x^2 y^2 = 1?




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All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}3xy6=0 x 2 3 x − y − 6 = 0 This equation is in standard form ax^ {2Actually, using wolfram alpha to graph it, I cant see where the center is and where the yaxis and zaxis and xaxis are $\endgroup$ – nany Jan 26 '15 at 235Plot 3x^22xyy^2=1 Natural Language;




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Graph Of X 2 Y 2 9
The graph of y=(2)^x is then What you don't see in the picture is that the graph has a large number of "holes" The only points on the graph have first coordinate x=p/q where p and q are integers with no common factors other than 1 and q is odd If p is even the point with first coordinate x=p/q is on the "upper" curve and is p is odd the point with first coordinate x=p/q isPrecalculus Graph x^2 (y1)^2=1 x2 (y − 1)2 = 1 x 2 ( y 1) 2 = 1 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h hGraph the parabola, y =x^21 by finding the turning point and using a table to find values for x and y




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